X^2+63x+90=0

Solution for X^2+63x+90=0 equation:

X^2+63X+90=0

a = 1; b = 63; c = +90;
Δ = b2-4ac
Δ = 632-4·1·90
Δ = 3609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3609}=\sqrt{9*401}=\sqrt{9}*\sqrt{401}=3\sqrt{401}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-3\sqrt{401}}{2*1}=\frac{-63-3\sqrt{401}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+3\sqrt{401}}{2*1}=\frac{-63+3\sqrt{401}}{2}
$